Session.EnumerateRemoteFiles is the right way.
$directoryInfo = $session.ListDirectory($remotePath)
$session.EnumerateRemoteFiles
EnumerationOptions of AllDirectories so I can be sure to always find the latest file. If there's a cleaner way to do this, I'm all ears. But, in my case, since the remote directory contains a collection of subdirectories, the ListDirectory method wasn't returning the collection of files. Hope this helps someone else! Cheers!
Where-Object clause to filter out directories from the Files collection does not seem to be working, as intended. I'm essentially using your whole script example from https://winscp.net/eng/docs/script_download_most_recent_file. I can manually step through the script, line by line and when I execute the following, a single file is never selected...
# Select the most recent file
$latest =
$directoryInfo.Files |
Where-Object { -Not $_.IsDirectory } |
Sort-Object LastWriteTime -Descending |
Select-Object -First 1
/ at the end I have added the / for the path and it appears to be working now.
$.
/usr/xxx/xxx.cvs? Is it a path you set $remotePath to? The purpose of the script is to find the latest file in a directory. So the $remotePath should be set to a path to the directory, not a specific path.
winscpnet.dll then an issue with the script DirectoryInfo was not a cmd, I guess that this line needed a $ before the command.
$, the script now moves onto the next issue.
Can't get attributes of file '/usr/xxx/xxx.cvs'